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x^2+72x-135=0
a = 1; b = 72; c = -135;
Δ = b2-4ac
Δ = 722-4·1·(-135)
Δ = 5724
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5724}=\sqrt{36*159}=\sqrt{36}*\sqrt{159}=6\sqrt{159}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-6\sqrt{159}}{2*1}=\frac{-72-6\sqrt{159}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+6\sqrt{159}}{2*1}=\frac{-72+6\sqrt{159}}{2} $
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